-17x^2+70x=0

Solution for -17x^2+70x=0 equation:

-17x^2+70x=0

a = -17; b = 70; c = 0;
Δ = b2-4ac
Δ = 702-4·(-17)·0
Δ = 4900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4900}=70$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(70)-70}{2*-17}=\frac{-140}{-34}
=4+2/17
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(70)+70}{2*-17}=\frac{0}{-34}
=0
$